Convert joule/centimeter to pound foot/square second
Please provide values below to convert joule/centimeter [J/cm] to pound foot/square second [lb*ft/s^2], or Convert pound foot/square second to joule/centimeter.
How to Convert Joule/centimeter to Pound Foot/square Second
1 J/cm = 723.301408014686 lb*ft/s^2
Example: convert 15 J/cm to lb*ft/s^2:
15 J/cm = 15 × 723.301408014686 lb*ft/s^2 = 10849.5211202203 lb*ft/s^2
Joule/centimeter to Pound Foot/square Second Conversion Table
| joule/centimeter | pound foot/square second |
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Joule/centimeter
The joule per centimeter (J/cm) is a unit of energy density or energy per unit length, representing the amount of energy (joules) contained or transferred per centimeter.
History/Origin
The unit derives from the SI unit of energy, the joule, combined with the centimeter as a unit of length. It has been used in contexts such as material science and physics to measure energy distribution over small distances.
Current Use
J/cm is used in fields like material testing, physics, and engineering to quantify energy density, especially in applications involving thin films, coatings, or localized energy measurements.
Pound Foot/square Second
The pound foot per square second (lb*ft/s^2) is a unit of force representing the force exerted by a one-pound mass accelerated at one foot per second squared.
History/Origin
This unit originated from the imperial system of units, primarily used in the United States, to quantify force based on the pound as a unit of mass and foot as a unit of distance, with seconds as the time unit. It is related to the pound-force (lbf) but includes a distance component, making it a derived unit in mechanics.
Current Use
The pound foot per square second is rarely used in modern practice; force is typically expressed in pound-force (lbf). When used, it appears in specific engineering contexts involving force calculations in imperial units, especially in classical mechanics and engineering analyses.